[alsa-devel] [PATCH] ALSA: hda/jack - Also add jack kctls for Conexant codecs
Mark Brown
broonie at opensource.wolfsonmicro.com
Thu Dec 22 15:12:51 CET 2011
On Thu, Dec 22, 2011 at 02:55:57PM +0100, Takashi Iwai wrote:
> Mark Brown wrote:
> > A pure addition can still cause problems as we roll out the same
> > interface into other drivers, for example if there's assumptions that
> > aren't generally true.
> In later future, yes. But I was talking about 3.3 kernel.
Once we've got a userspace interface we're pretty much stuck with it...
> > I'm guessing that as this is just a simple boolean each jack will have a
> > series of controls like "Headset Jack Headphone" and "Headset Jack
> > Microphone" or whatever and userspace should match them all together in
> > the same way that it does for Volume and Switch controls?
> My current assumption is so, too. OTOH, if a single jack must provide
> several values inevitably, it may take an integer or an enum, in
> theory. But I think (and hope) this wouldn't happen.
Supporting multiple objects on a single jack is a very basic requirement
in order to support headsets (which exist on PCs as well, the MacBooks
for example) - we can usually distinguish between at least headset and
headphone. I think if we're going to do this via a single multi-state
control rather than a series of booleans it'd need to be an enum for
usability ("an object of type 2!"), Android uses integers and it's
pretty miserable for usability.
> > That sounds
> > like it'll work well, we just need to define some strings for standard
> > jacks and conections.
> Yeah. Unfortunately this standardization isn't always trivial,
> especially when multiple jacks are present with the same type...
I was thinking more about the things you might detect rather than the
jacks, that's a much more tractable problem.
> My idea is to give some association between this jack kctl and another
> kctl, in a simple way like TLV. But it's likely a new year's dream.
Associating the jacks with the audio routes is definitely a separate
problem.
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