[alsa-devel] [PATCH v2 3/6] dma: Add a jz4740 dmaengine driver
lars at metafoo.de
Wed Jun 12 14:07:10 CEST 2013
On 06/12/2013 07:38 AM, Vinod Koul wrote:
> On Mon, Jun 10, 2013 at 07:29:46PM +0200, Lars-Peter Clausen wrote:
>> On 05/30/2013 08:46 PM, Lars-Peter Clausen wrote:
>>>>> +static int jz4740_dma_alloc_chan_resources(struct dma_chan *c)
>>>>> + struct jz4740_dmaengine_chan *chan = to_jz4740_dma_chan(c);
>>>>> + chan->jz_chan = jz4740_dma_request(chan, NULL);
>>>>> + if (!chan->jz_chan)
>>>>> + return -EBUSY;
>>>>> + jz4740_dma_set_complete_cb(chan->jz_chan, jz4740_dma_complete_cb);
>>>>> + return 0;
>>>> Sorry, I didnt reply on this one. The API expects you to allocate a pool of
>>>> descriptors. These descriptors are to be used in .device_prep_xxx calls later.
>>> The size of the descriptor is not fixed, so they can not be pre-allocated. And
>>> this is nothing new either, most of the more recently added dmaengine drivers
>>> allocate their descriptors on demand.
>> Vinod, are you ok with this explanation?
> Sorry, I was travelling...
> Can you explain more of a bit when you say size is not fixed.
This is the function that allocates the descriptor:
static struct jz4740_dma_desc *jz4740_dma_alloc_desc(unsigned int num_sgs)
return kzalloc(sizeof(struct jz4740_dma_desc) +
sizeof(struct jz4740_dma_sg) * num_sgs, GFP_ATOMIC);
So the size depends on the entries in the sg list.
> Why would it be
> issue if we allocate descriptors at the alloc_chan. The idea is that you
> preallocated pool at alloc_chan and since the .device_prep_xxx calls can be
> called from atomic context as well, you dont need to do this later. You can use use
> these descriptors at that time. The idea is keep rotating the descriptors from
> free poll to used one
Yes, I know all that. And it makes sense to use a pool in certain
situations, e.g. if the hardware only supports a limited set of physical
descriptors. But in this case the descriptors are completely virtual.
Forcing the driver to use a pool would make it more complex, use more memory
and also a bit slower (although probably not noticeable).
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